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131121433 is a prime number
BaseRepresentation
bin1111101000011…
…00000100011001
3100010201122210101
413310030010121
5232031341213
621002215401
73151341142
oct764140431
9303648711
10131121433
1168018523
1237ab4561
132121c061
14135b2ac9
15b7a0bdd
hex7d0c119

131121433 has 2 divisors, whose sum is σ = 131121434. Its totient is φ = 131121432.

The previous prime is 131121409. The next prime is 131121439. The reversal of 131121433 is 334121131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77933584 + 53187849 = 8828^2 + 7293^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131121433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131121433.

It is not a weakly prime, because it can be changed into another prime (131121439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560716 + 65560717.

It is an arithmetic number, because the mean of its divisors is an integer number (65560717).

Almost surely, 2131121433 is an apocalyptic number.

It is an amenable number.

131121433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131121433 is an equidigital number, since it uses as much as digits as its factorization.

131121433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216, while the sum is 19.

The square root of 131121433 is about 11450.8267387119. The cubic root of 131121433 is about 508.0321876499.

Adding to 131121433 its reverse (334121131), we get a palindrome (465242564).

The spelling of 131121433 in words is "one hundred thirty-one million, one hundred twenty-one thousand, four hundred thirty-three".