13112233100121 has 4 divisors (see below), whose sum is σ = 17482977466832. Its totient is φ = 8741488733412.

The previous prime is 13112233100069. The next prime is 13112233100227. The reversal of 13112233100121 is 12100133221131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13112233100121 - 2⁷ = 13112233099993 is a prime.

It is a super-3 number, since 3×13112233100121³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112233100621) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185372183351 + ... + 2185372183356.

It is an arithmetic number, because the mean of its divisors is an integer number (4370744366708).

Almost surely, 2^{13112233100121} is an apocalyptic number.

It is an amenable number.

13112233100121 is a deficient number, since it is larger than the sum of its proper divisors (4370744366711).

13112233100121 is an equidigital number, since it uses as much as digits as its factorization.

13112233100121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4370744366710.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 13112233100121 its reverse (12100133221131), we get a palindrome (25212366321252).

The spelling of 13112233100121 in words is "thirteen trillion, one hundred twelve billion, two hundred thirty-three million, one hundred thousand, one hundred twenty-one".