Base | Representation |
---|---|
bin | 10011000101001011011… |
… | …001100011110001101001 |
3 | 11122100111212121101221112 |
4 | 103011023121203301221 |
5 | 132440344341012432 |
6 | 2442212025520105 |
7 | 163506334146533 |
oct | 23051331436151 |
9 | 4570455541845 |
10 | 1311230016617 |
11 | 4660a9184964 |
12 | 192160343035 |
13 | 968578887a1 |
14 | 4766cc12853 |
15 | 24194c9c7b2 |
hex | 1314b663c69 |
1311230016617 has 2 divisors, whose sum is σ = 1311230016618. Its totient is φ = 1311230016616.
The previous prime is 1311230016521. The next prime is 1311230016637. The reversal of 1311230016617 is 7166100321131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1120589499241 + 190640517376 = 1058579^2 + 436624^2 .
It is an emirp because it is prime and its reverse (7166100321131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311230016617 - 210 = 1311230015593 is a prime.
It is a super-2 number, since 2×13112300166172 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1311230016637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655615008308 + 655615008309.
It is an arithmetic number, because the mean of its divisors is an integer number (655615008309).
Almost surely, 21311230016617 is an apocalyptic number.
It is an amenable number.
1311230016617 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311230016617 is an equidigital number, since it uses as much as digits as its factorization.
1311230016617 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 32.
Adding to 1311230016617 its reverse (7166100321131), we get a palindrome (8477330337748).
The spelling of 1311230016617 in words is "one trillion, three hundred eleven billion, two hundred thirty million, sixteen thousand, six hundred seventeen".
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