Base | Representation |
---|---|
bin | 10011000101001011011… |
… | …011011010010011000011 |
3 | 11122100111220112001212202 |
4 | 103011023123122103003 |
5 | 132440400002031313 |
6 | 2442212044143415 |
7 | 163506341241065 |
oct | 23051333322303 |
9 | 4570456461782 |
10 | 1311230502083 |
11 | 4660a9486677 |
12 | 192160537b6b |
13 | 968579c8748 |
14 | 4766ccdb735 |
15 | 24194d46558 |
hex | 1314b6da4c3 |
1311230502083 has 2 divisors, whose sum is σ = 1311230502084. Its totient is φ = 1311230502082.
The previous prime is 1311230502041. The next prime is 1311230502137. The reversal of 1311230502083 is 3802050321131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311230502083 - 214 = 1311230485699 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311230502583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655615251041 + 655615251042.
It is an arithmetic number, because the mean of its divisors is an integer number (655615251042).
Almost surely, 21311230502083 is an apocalyptic number.
1311230502083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311230502083 is an equidigital number, since it uses as much as digits as its factorization.
1311230502083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 29.
The spelling of 1311230502083 in words is "one trillion, three hundred eleven billion, two hundred thirty million, five hundred two thousand, eighty-three".
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