Base | Representation |
---|---|
bin | 1011111011001111001010… |
… | …0101001110001110110011 |
3 | 1201102112011102122020211202 |
4 | 2332303302211032032303 |
5 | 3204313002332000113 |
6 | 43515413450201415 |
7 | 2522222160203051 |
oct | 276636245161663 |
9 | 51375142566752 |
10 | 13112310031283 |
11 | 41a59991a2571 |
12 | 157930612326b |
13 | 741640930328 |
14 | 3348d3d291d1 |
15 | 17b134483258 |
hex | becf294e3b3 |
13112310031283 has 2 divisors, whose sum is σ = 13112310031284. Its totient is φ = 13112310031282.
The previous prime is 13112310031279. The next prime is 13112310031397. The reversal of 13112310031283 is 38213001321131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13112310031283 - 22 = 13112310031279 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13112310031253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556155015641 + 6556155015642.
It is an arithmetic number, because the mean of its divisors is an integer number (6556155015642).
Almost surely, 213112310031283 is an apocalyptic number.
13112310031283 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112310031283 is an equidigital number, since it uses as much as digits as its factorization.
13112310031283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 13112310031283 in words is "thirteen trillion, one hundred twelve billion, three hundred ten million, thirty-one thousand, two hundred eighty-three".
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