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13112321202003 = 34370773734001
BaseRepresentation
bin1011111011001111001100…
…1111110101011101010011
31201102112012012122210012010
42332303303033311131103
53204313013211431003
643515414525434003
72522222354146542
oct276636317653523
951375165583163
1013112321202003
1141a59a4532271
121579309a0b903
13741643041a1a
143348d55d6159
1517b13543d003
hexbecf33f5753

13112321202003 has 4 divisors (see below), whose sum is σ = 17483094936008. Its totient is φ = 8741547468000.

The previous prime is 13112321201971. The next prime is 13112321202017. The reversal of 13112321202003 is 30020212321131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13112321202003 - 25 = 13112321201971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112321202023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185386866998 + ... + 2185386867003.

It is an arithmetic number, because the mean of its divisors is an integer number (4370773734002).

Almost surely, 213112321202003 is an apocalyptic number.

13112321202003 is a deficient number, since it is larger than the sum of its proper divisors (4370773734005).

13112321202003 is an equidigital number, since it uses as much as digits as its factorization.

13112321202003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4370773734004.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13112321202003 its reverse (30020212321131), we get a palindrome (43132533523134).

The spelling of 13112321202003 in words is "thirteen trillion, one hundred twelve billion, three hundred twenty-one million, two hundred two thousand, three".

Divisors: 1 3 4370773734001 13112321202003