Base | Representation |
---|---|
bin | 1011111011001111001100… |
… | …1111110101011101010011 |
3 | 1201102112012012122210012010 |
4 | 2332303303033311131103 |
5 | 3204313013211431003 |
6 | 43515414525434003 |
7 | 2522222354146542 |
oct | 276636317653523 |
9 | 51375165583163 |
10 | 13112321202003 |
11 | 41a59a4532271 |
12 | 1579309a0b903 |
13 | 741643041a1a |
14 | 3348d55d6159 |
15 | 17b13543d003 |
hex | becf33f5753 |
13112321202003 has 4 divisors (see below), whose sum is σ = 17483094936008. Its totient is φ = 8741547468000.
The previous prime is 13112321201971. The next prime is 13112321202017. The reversal of 13112321202003 is 30020212321131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13112321202003 - 25 = 13112321201971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13112321202023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185386866998 + ... + 2185386867003.
It is an arithmetic number, because the mean of its divisors is an integer number (4370773734002).
Almost surely, 213112321202003 is an apocalyptic number.
13112321202003 is a deficient number, since it is larger than the sum of its proper divisors (4370773734005).
13112321202003 is an equidigital number, since it uses as much as digits as its factorization.
13112321202003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4370773734004.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13112321202003 its reverse (30020212321131), we get a palindrome (43132533523134).
The spelling of 13112321202003 in words is "thirteen trillion, one hundred twelve billion, three hundred twenty-one million, two hundred two thousand, three".
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