Base | Representation |
---|---|
bin | 111101000011110001… |
… | …1011100010101101001 |
3 | 110112110012111110012202 |
4 | 1322013203130111221 |
5 | 4122020021443103 |
6 | 140123121545545 |
7 | 12321233046332 |
oct | 1720743342551 |
9 | 415405443182 |
10 | 131123234153 |
11 | 5067771361a |
12 | 214b4aa52b5 |
13 | c4987cba22 |
14 | 64bc735289 |
15 | 3626788988 |
hex | 1e878dc569 |
131123234153 has 2 divisors, whose sum is σ = 131123234154. Its totient is φ = 131123234152.
The previous prime is 131123234129. The next prime is 131123234161. The reversal of 131123234153 is 351432321131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131093236624 + 29997529 = 362068^2 + 5477^2 .
It is an emirp because it is prime and its reverse (351432321131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131123234153 - 28 = 131123233897 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (131123234173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65561617076 + 65561617077.
It is an arithmetic number, because the mean of its divisors is an integer number (65561617077).
Almost surely, 2131123234153 is an apocalyptic number.
It is an amenable number.
131123234153 is a deficient number, since it is larger than the sum of its proper divisors (1).
131123234153 is an equidigital number, since it uses as much as digits as its factorization.
131123234153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480, while the sum is 29.
Adding to 131123234153 its reverse (351432321131), we get a palindrome (482555555284).
The spelling of 131123234153 in words is "one hundred thirty-one billion, one hundred twenty-three million, two hundred thirty-four thousand, one hundred fifty-three".
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