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13112330047907 is a prime number
BaseRepresentation
bin1011111011001111001111…
…0001100101000110100011
31201102112012211022012111012
42332303303301211012203
53204313022443013112
643515415443211135
72522222522301416
oct276636361450643
951375184265435
1013112330047907
1141a59a9524332
121579310976aab
13741644b1b19c
143348d6859b7d
1517b1360d9022
hexbecf3c651a3

13112330047907 has 2 divisors, whose sum is σ = 13112330047908. Its totient is φ = 13112330047906.

The previous prime is 13112330047897. The next prime is 13112330047967. The reversal of 13112330047907 is 70974003321131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13112330047907 - 210 = 13112330046883 is a prime.

It is a super-3 number, since 3×131123300479073 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13112330047967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165023953 + 6556165023954.

It is an arithmetic number, because the mean of its divisors is an integer number (6556165023954).

Almost surely, 213112330047907 is an apocalyptic number.

13112330047907 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112330047907 is an equidigital number, since it uses as much as digits as its factorization.

13112330047907 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 95256, while the sum is 41.

The spelling of 13112330047907 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, forty-seven thousand, nine hundred seven".