Base | Representation |
---|---|
bin | 11000011011000111… |
… | …01001101000110001 |
3 | 1020211211012110110001 |
4 | 30031203221220301 |
5 | 203323230220111 |
6 | 10005043110001 |
7 | 642636101251 |
oct | 141543515061 |
9 | 36754173401 |
10 | 13112351281 |
11 | 5619642657 |
12 | 265b372301 |
13 | 130c74b353 |
14 | 8c5653961 |
15 | 51b2461c1 |
hex | 30d8e9a31 |
13112351281 has 2 divisors, whose sum is σ = 13112351282. Its totient is φ = 13112351280.
The previous prime is 13112351257. The next prime is 13112351321. The reversal of 13112351281 is 18215321131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13041640000 + 70711281 = 114200^2 + 8409^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112351281 - 25 = 13112351249 is a prime.
It is a super-2 number, since 2×131123512812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13112351881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556175640 + 6556175641.
It is an arithmetic number, because the mean of its divisors is an integer number (6556175641).
Almost surely, 213112351281 is an apocalyptic number.
It is an amenable number.
13112351281 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112351281 is an equidigital number, since it uses as much as digits as its factorization.
13112351281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 28.
The spelling of 13112351281 in words is "thirteen billion, one hundred twelve million, three hundred fifty-one thousand, two hundred eighty-one".
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