Base | Representation |
---|---|
bin | 1011111011001111100001… |
… | …0000011000011001100011 |
3 | 1201102112102001202220120201 |
4 | 2332303320100120121203 |
5 | 3204313201214344303 |
6 | 43515431130450031 |
7 | 2522224424323615 |
oct | 276637020303143 |
9 | 51375361686521 |
10 | 13112405231203 |
11 | 41a5a37a05693 |
12 | 1579331b93917 |
13 | 741657583045 |
14 | 33490282adb5 |
15 | 17b13c9da81d |
hex | becf8418663 |
13112405231203 has 2 divisors, whose sum is σ = 13112405231204. Its totient is φ = 13112405231202.
The previous prime is 13112405231197. The next prime is 13112405231213. The reversal of 13112405231203 is 30213250421131.
13112405231203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (30213250421131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112405231203 is a prime.
It is not a weakly prime, because it can be changed into another prime (13112405231213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556202615601 + 6556202615602.
It is an arithmetic number, because the mean of its divisors is an integer number (6556202615602).
Almost surely, 213112405231203 is an apocalyptic number.
13112405231203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112405231203 is an equidigital number, since it uses as much as digits as its factorization.
13112405231203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13112405231203 its reverse (30213250421131), we get a palindrome (43325655652334).
The spelling of 13112405231203 in words is "thirteen trillion, one hundred twelve billion, four hundred five million, two hundred thirty-one thousand, two hundred three".
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