Base | Representation |
---|---|
bin | 10011000101001100000… |
… | …100110010101111111001 |
3 | 11122100112122221012121112 |
4 | 103011030010302233321 |
5 | 132440410241201022 |
6 | 2442213112450105 |
7 | 163506532402055 |
oct | 23051404625771 |
9 | 4570478835545 |
10 | 1311241350137 |
11 | 466104615a04 |
12 | 1921640a9935 |
13 | 9685a026304 |
14 | 47670522c65 |
15 | 24195c8a8e2 |
hex | 1314c132bf9 |
1311241350137 has 2 divisors, whose sum is σ = 1311241350138. Its totient is φ = 1311241350136.
The previous prime is 1311241350131. The next prime is 1311241350163. The reversal of 1311241350137 is 7310531421131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1116496542736 + 194744807401 = 1056644^2 + 441299^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311241350137 - 220 = 1311240301561 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311241350131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655620675068 + 655620675069.
It is an arithmetic number, because the mean of its divisors is an integer number (655620675069).
Almost surely, 21311241350137 is an apocalyptic number.
It is an amenable number.
1311241350137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311241350137 is an equidigital number, since it uses as much as digits as its factorization.
1311241350137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 32.
Adding to 1311241350137 its reverse (7310531421131), we get a palindrome (8621772771268).
The spelling of 1311241350137 in words is "one trillion, three hundred eleven billion, two hundred forty-one million, three hundred fifty thousand, one hundred thirty-seven".
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