Base | Representation |
---|---|
bin | 1011111011001111101001… |
… | …0101101101110011100001 |
3 | 1201102112111111112200211222 |
4 | 2332303322111231303201 |
5 | 3204313234141342113 |
6 | 43515434415544425 |
7 | 2522225330401121 |
oct | 276637225556341 |
9 | 51375444480758 |
10 | 13112440184033 |
11 | 41a5a55709223 |
12 | 157934182b115 |
13 | 7416618a04a8 |
14 | 334907328c81 |
15 | 17b140ae1e08 |
hex | becfa56dce1 |
13112440184033 has 2 divisors, whose sum is σ = 13112440184034. Its totient is φ = 13112440184032.
The previous prime is 13112440184027. The next prime is 13112440184069. The reversal of 13112440184033 is 33048104421131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11127981954769 + 1984458229264 = 3335863^2 + 1408708^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112440184033 - 24 = 13112440184017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13112440183984 and 13112440184002.
It is not a weakly prime, because it can be changed into another prime (13112440180033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556220092016 + 6556220092017.
It is an arithmetic number, because the mean of its divisors is an integer number (6556220092017).
Almost surely, 213112440184033 is an apocalyptic number.
It is an amenable number.
13112440184033 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112440184033 is an equidigital number, since it uses as much as digits as its factorization.
13112440184033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 35.
The spelling of 13112440184033 in words is "thirteen trillion, one hundred twelve billion, four hundred forty million, one hundred eighty-four thousand, thirty-three".
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