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13112440184033 is a prime number
BaseRepresentation
bin1011111011001111101001…
…0101101101110011100001
31201102112111111112200211222
42332303322111231303201
53204313234141342113
643515434415544425
72522225330401121
oct276637225556341
951375444480758
1013112440184033
1141a5a55709223
12157934182b115
137416618a04a8
14334907328c81
1517b140ae1e08
hexbecfa56dce1

13112440184033 has 2 divisors, whose sum is σ = 13112440184034. Its totient is φ = 13112440184032.

The previous prime is 13112440184027. The next prime is 13112440184069. The reversal of 13112440184033 is 33048104421131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11127981954769 + 1984458229264 = 3335863^2 + 1408708^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112440184033 - 24 = 13112440184017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13112440183984 and 13112440184002.

It is not a weakly prime, because it can be changed into another prime (13112440180033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556220092016 + 6556220092017.

It is an arithmetic number, because the mean of its divisors is an integer number (6556220092017).

Almost surely, 213112440184033 is an apocalyptic number.

It is an amenable number.

13112440184033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112440184033 is an equidigital number, since it uses as much as digits as its factorization.

13112440184033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 35.

The spelling of 13112440184033 in words is "thirteen trillion, one hundred twelve billion, four hundred forty million, one hundred eighty-four thousand, thirty-three".