Base | Representation |
---|---|
bin | 111101000011111010… |
… | …0110001011101110011 |
3 | 110112110112001021000111 |
4 | 1322013310301131303 |
5 | 4122022202332024 |
6 | 140123403202151 |
7 | 12321316500232 |
oct | 1720764613563 |
9 | 415415037014 |
10 | 131127777139 |
11 | 5067a236857 |
12 | 214b6516357 |
13 | c49972c798 |
14 | 64bd198b19 |
15 | 3626d84a94 |
hex | 1e87d31773 |
131127777139 has 2 divisors, whose sum is σ = 131127777140. Its totient is φ = 131127777138.
The previous prime is 131127777119. The next prime is 131127777247. The reversal of 131127777139 is 931777721131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131127777139 - 211 = 131127775091 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131127777092 and 131127777101.
It is not a weakly prime, because it can be changed into another prime (131127777119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65563888569 + 65563888570.
It is an arithmetic number, because the mean of its divisors is an integer number (65563888570).
Almost surely, 2131127777139 is an apocalyptic number.
131127777139 is a deficient number, since it is larger than the sum of its proper divisors (1).
131127777139 is an equidigital number, since it uses as much as digits as its factorization.
131127777139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 388962, while the sum is 49.
The spelling of 131127777139 in words is "one hundred thirty-one billion, one hundred twenty-seven million, seven hundred seventy-seven thousand, one hundred thirty-nine".
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