Base | Representation |
---|---|
bin | 1011111011010001001010… |
… | …1001110011000111111011 |
3 | 1201102120112221010001221111 |
4 | 2332310102221303013323 |
5 | 3204320103103230013 |
6 | 43515543111021151 |
7 | 2522241412551025 |
oct | 276642251630773 |
9 | 51376487101844 |
10 | 13112848101883 |
11 | 41a61449a1a12 |
12 | 157943636a7b7 |
13 | 7416c82549ba |
14 | 334945591015 |
15 | 17b16681b73d |
hex | bed12a731fb |
13112848101883 has 8 divisors (see below), whose sum is σ = 13581741584880. Its totient is φ = 12645069706080.
The previous prime is 13112848101833. The next prime is 13112848101889. The reversal of 13112848101883 is 38810184821131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112848101883 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13112848101889) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 278747860 + ... + 278794897.
It is an arithmetic number, because the mean of its divisors is an integer number (1697717698110).
Almost surely, 213112848101883 is an apocalyptic number.
13112848101883 is a deficient number, since it is larger than the sum of its proper divisors (468893482997).
13112848101883 is an equidigital number, since it uses as much as digits as its factorization.
13112848101883 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 557543597.
The product of its (nonzero) digits is 294912, while the sum is 49.
The spelling of 13112848101883 in words is "thirteen trillion, one hundred twelve billion, eight hundred forty-eight million, one hundred one thousand, eight hundred eighty-three".
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