Base | Representation |
---|---|
bin | 11101110100001100010110… |
… | …011010000011010111001011 |
3 | 122012021220111201121011010021 |
4 | 131310030112122003113023 |
5 | 114141413241221124233 |
6 | 1142520144540401311 |
7 | 36422555125035643 |
oct | 3564142632032713 |
9 | 565256451534107 |
10 | 131130022442443 |
11 | 38866a26130622 |
12 | 12859a63246237 |
13 | 582267b2825ab |
14 | 2454a26a73523 |
15 | 1025ed5b07e2d |
hex | 7743166835cb |
131130022442443 has 2 divisors, whose sum is σ = 131130022442444. Its totient is φ = 131130022442442.
The previous prime is 131130022442369. The next prime is 131130022442483. The reversal of 131130022442443 is 344244220031131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131130022442443 - 213 = 131130022434251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131130022442399 and 131130022442408.
It is not a weakly prime, because it can be changed into another prime (131130022442483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565011221221 + 65565011221222.
It is an arithmetic number, because the mean of its divisors is an integer number (65565011221222).
Almost surely, 2131130022442443 is an apocalyptic number.
131130022442443 is a deficient number, since it is larger than the sum of its proper divisors (1).
131130022442443 is an equidigital number, since it uses as much as digits as its factorization.
131130022442443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 131130022442443 its reverse (344244220031131), we get a palindrome (475374242473574).
The spelling of 131130022442443 in words is "one hundred thirty-one trillion, one hundred thirty billion, twenty-two million, four hundred forty-two thousand, four hundred forty-three".
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