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13113003201 = 34371001067
BaseRepresentation
bin11000011011001100…
…01000110011000001
31020211212102120201020
430031212020303001
5203323412100301
610005105100053
7642644455014
oct141546106301
936755376636
1013113003201
115619a48431
12265b627629
13130c918cbc
148c578337b
1551b324436
hex30d988cc1

13113003201 has 4 divisors (see below), whose sum is σ = 17484004272. Its totient is φ = 8742002132.

The previous prime is 13113003173. The next prime is 13113003221. The reversal of 13113003201 is 10230031131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13113003201 - 215 = 13112970433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13113003221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185500531 + ... + 2185500536.

It is an arithmetic number, because the mean of its divisors is an integer number (4371001068).

Almost surely, 213113003201 is an apocalyptic number.

It is an amenable number.

13113003201 is a deficient number, since it is larger than the sum of its proper divisors (4371001071).

13113003201 is an equidigital number, since it uses as much as digits as its factorization.

13113003201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4371001070.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13113003201 its reverse (10230031131), we get a palindrome (23343034332).

The spelling of 13113003201 in words is "thirteen billion, one hundred thirteen million, three thousand, two hundred one".

Divisors: 1 3 4371001067 13113003201