Base | Representation |
---|---|
bin | 11000011011001100… |
… | …01101110111111001 |
3 | 1020211212110122020022 |
4 | 30031212031313321 |
5 | 203323413231433 |
6 | 10005105340225 |
7 | 642644602436 |
oct | 141546156771 |
9 | 36755418208 |
10 | 13113023993 |
11 | 5619a62013 |
12 | 265b637675 |
13 | 130c9255c4 |
14 | 8c578ab8d |
15 | 51b32a698 |
hex | 30d98ddf9 |
13113023993 has 2 divisors, whose sum is σ = 13113023994. Its totient is φ = 13113023992.
The previous prime is 13113023981. The next prime is 13113024013. The reversal of 13113023993 is 39932031131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12469742224 + 643281769 = 111668^2 + 25363^2 .
It is a cyclic number.
It is not a de Polignac number, because 13113023993 - 24 = 13113023977 is a prime.
It is not a weakly prime, because it can be changed into another prime (13113020993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556511996 + 6556511997.
It is an arithmetic number, because the mean of its divisors is an integer number (6556511997).
Almost surely, 213113023993 is an apocalyptic number.
It is an amenable number.
13113023993 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113023993 is an equidigital number, since it uses as much as digits as its factorization.
13113023993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 35.
The spelling of 13113023993 in words is "thirteen billion, one hundred thirteen million, twenty-three thousand, nine hundred ninety-three".
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