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13113102002443 is a prime number
BaseRepresentation
bin1011111011010010000111…
…0010010110100100001011
31201102121012121212120000221
42332310201302112210023
53204321113103034233
643520024221010511
72522250614636632
oct276644162264413
951377177776027
1013113102002443
1141a626524a193
1215794a73b3a37
13741738a31911
1433496b1a4519
1517b17dc7142d
hexbed21c9690b

13113102002443 has 2 divisors, whose sum is σ = 13113102002444. Its totient is φ = 13113102002442.

The previous prime is 13113102002347. The next prime is 13113102002461. The reversal of 13113102002443 is 34420020131131.

13113102002443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13113102002443 - 229 = 13112565131531 is a prime.

It is not a weakly prime, because it can be changed into another prime (13113102008443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556551001221 + 6556551001222.

It is an arithmetic number, because the mean of its divisors is an integer number (6556551001222).

Almost surely, 213113102002443 is an apocalyptic number.

13113102002443 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113102002443 is an equidigital number, since it uses as much as digits as its factorization.

13113102002443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13113102002443 its reverse (34420020131131), we get a palindrome (47533122133574).

The spelling of 13113102002443 in words is "thirteen trillion, one hundred thirteen billion, one hundred two million, two thousand, four hundred forty-three".