131131101323 has 4 divisors (see below), whose sum is σ = 131131827048. Its totient is φ = 131130375600.

The previous prime is 131131101317. The next prime is 131131101331. The reversal of 131131101323 is 323101131131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 323101131131 = 107473 ⋅3006347.

It is a cyclic number.

It is not a de Polignac number, because 131131101323 - 2⁴ = 131131101307 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131131101295 and 131131101304.

It is not an unprimeable number, because it can be changed into a prime (131131101373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146648 + ... + 532698.

It is an arithmetic number, because the mean of its divisors is an integer number (32782956762).

Almost surely, 2^131131101323 is an apocalyptic number.

131131101323 is a deficient number, since it is larger than the sum of its proper divisors (725725).

131131101323 is an equidigital number, since it uses as much as digits as its factorization.

131131101323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 725724.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 131131101323 its reverse (323101131131), we get a palindrome (454232232454).

The spelling of 131131101323 in words is "one hundred thirty-one billion, one hundred thirty-one million, one hundred one thousand, three hundred twenty-three".