Base | Representation |
---|---|
bin | 1011111011010010001001… |
… | …1000111010010000101001 |
3 | 1201102121020022220002011101 |
4 | 2332310202120322100221 |
5 | 3204321123200010441 |
6 | 43520025221401401 |
7 | 2522251066565242 |
oct | 276644230722051 |
9 | 51377208802141 |
10 | 13113112110121 |
11 | 41a626aa23241 |
12 | 15794aa869261 |
13 | 74173ab604aa |
14 | 33496c675cc9 |
15 | 17b17eabb231 |
hex | bed2263a429 |
13113112110121 has 2 divisors, whose sum is σ = 13113112110122. Its totient is φ = 13113112110120.
The previous prime is 13113112110107. The next prime is 13113112110157. The reversal of 13113112110121 is 12101121131131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10048494244096 + 3064617866025 = 3169936^2 + 1750605^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13113112110121 is a prime.
It is not a weakly prime, because it can be changed into another prime (13113112110191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556556055060 + 6556556055061.
It is an arithmetic number, because the mean of its divisors is an integer number (6556556055061).
Almost surely, 213113112110121 is an apocalyptic number.
It is an amenable number.
13113112110121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113112110121 is an equidigital number, since it uses as much as digits as its factorization.
13113112110121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 19.
Adding to 13113112110121 its reverse (12101121131131), we get a palindrome (25214233241252).
The spelling of 13113112110121 in words is "thirteen trillion, one hundred thirteen billion, one hundred twelve million, one hundred ten thousand, one hundred twenty-one".
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