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13113112110121 is a prime number
BaseRepresentation
bin1011111011010010001001…
…1000111010010000101001
31201102121020022220002011101
42332310202120322100221
53204321123200010441
643520025221401401
72522251066565242
oct276644230722051
951377208802141
1013113112110121
1141a626aa23241
1215794aa869261
1374173ab604aa
1433496c675cc9
1517b17eabb231
hexbed2263a429

13113112110121 has 2 divisors, whose sum is σ = 13113112110122. Its totient is φ = 13113112110120.

The previous prime is 13113112110107. The next prime is 13113112110157. The reversal of 13113112110121 is 12101121131131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10048494244096 + 3064617866025 = 3169936^2 + 1750605^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13113112110121 is a prime.

It is not a weakly prime, because it can be changed into another prime (13113112110191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556556055060 + 6556556055061.

It is an arithmetic number, because the mean of its divisors is an integer number (6556556055061).

Almost surely, 213113112110121 is an apocalyptic number.

It is an amenable number.

13113112110121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113112110121 is an equidigital number, since it uses as much as digits as its factorization.

13113112110121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 19.

Adding to 13113112110121 its reverse (12101121131131), we get a palindrome (25214233241252).

The spelling of 13113112110121 in words is "thirteen trillion, one hundred thirteen billion, one hundred twelve million, one hundred ten thousand, one hundred twenty-one".