Base | Representation |
---|---|
bin | 111101000100000000… |
… | …1110111111000110001 |
3 | 110112110202111201211010 |
4 | 1322020001313320301 |
5 | 4122024042230223 |
6 | 140124004541133 |
7 | 12321360622344 |
oct | 1721001677061 |
9 | 415422451733 |
10 | 131131211313 |
11 | 50681171a13 |
12 | 214b76b17a9 |
13 | c49a36293b |
14 | 64bd81045b |
15 | 3627312393 |
hex | 1e88077e31 |
131131211313 has 4 divisors (see below), whose sum is σ = 174841615088. Its totient is φ = 87420807540.
The previous prime is 131131211293. The next prime is 131131211377. The reversal of 131131211313 is 313112131131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 131131211313 - 29 = 131131210801 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131131211313.
It is not an unprimeable number, because it can be changed into a prime (131131211383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21855201883 + ... + 21855201888.
It is an arithmetic number, because the mean of its divisors is an integer number (43710403772).
Almost surely, 2131131211313 is an apocalyptic number.
It is an amenable number.
131131211313 is a deficient number, since it is larger than the sum of its proper divisors (43710403775).
131131211313 is an equidigital number, since it uses as much as digits as its factorization.
131131211313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43710403774.
The product of its digits is 162, while the sum is 21.
Adding to 131131211313 its reverse (313112131131), we get a palindrome (444243342444).
The spelling of 131131211313 in words is "one hundred thirty-one billion, one hundred thirty-one million, two hundred eleven thousand, three hundred thirteen".
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