Base | Representation |
---|---|
bin | 11101110100001101100000… |
… | …000000110000011011110111 |
3 | 122012022000200210020200221111 |
4 | 131310031200000300123313 |
5 | 114141423303333402203 |
6 | 1142520511252255451 |
7 | 36422630541260344 |
oct | 3564154000603367 |
9 | 565260623220844 |
10 | 131131257325303 |
11 | 388674aa1a2374 |
12 | 1285a148911587 |
13 | 582281706b401 |
14 | 2454b02a837cb |
15 | 102605923426d |
hex | 7743600306f7 |
131131257325303 has 16 divisors (see below), whose sum is σ = 135128184190560. Its totient is φ = 127158878560896.
The previous prime is 131131257325283. The next prime is 131131257325351. The reversal of 131131257325303 is 303523752131131.
It is a cyclic number.
It is not a de Polignac number, because 131131257325303 - 29 = 131131257324791 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131131257320303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8255013 + ... + 18177121.
It is an arithmetic number, because the mean of its divisors is an integer number (8445511511910).
Almost surely, 2131131257325303 is an apocalyptic number.
131131257325303 is a deficient number, since it is larger than the sum of its proper divisors (3996926865257).
131131257325303 is an equidigital number, since it uses as much as digits as its factorization.
131131257325303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9923346.
The product of its (nonzero) digits is 170100, while the sum is 40.
The spelling of 131131257325303 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, two hundred fifty-seven million, three hundred twenty-five thousand, three hundred three".
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