Base | Representation |
---|---|
bin | 11101110100001101100100… |
… | …111101101101110010010011 |
3 | 122012022000220120121001100022 |
4 | 131310031210331231302103 |
5 | 114141423441121222344 |
6 | 1142520523421214055 |
7 | 36422632600436624 |
oct | 3564154475556223 |
9 | 565260816531308 |
10 | 131131340414099 |
11 | 388675420931a3 |
12 | 1285a17070132b |
13 | 582282b34068c |
14 | 2454b0db11a4b |
15 | 10260616980ee |
hex | 774364f6dc93 |
131131340414099 has 2 divisors, whose sum is σ = 131131340414100. Its totient is φ = 131131340414098.
The previous prime is 131131340414051. The next prime is 131131340414213. The reversal of 131131340414099 is 990414043131131.
It is a weak prime.
It is an emirp because it is prime and its reverse (990414043131131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131131340414099 is a prime.
It is not a weakly prime, because it can be changed into another prime (131131340434099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565670207049 + 65565670207050.
It is an arithmetic number, because the mean of its divisors is an integer number (65565670207050).
Almost surely, 2131131340414099 is an apocalyptic number.
131131340414099 is a deficient number, since it is larger than the sum of its proper divisors (1).
131131340414099 is an equidigital number, since it uses as much as digits as its factorization.
131131340414099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 44.
The spelling of 131131340414099 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, three hundred forty million, four hundred fourteen thousand, ninety-nine".
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