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131132003 is a prime number
BaseRepresentation
bin1111101000011…
…10101001100011
3100010202012021212
413310032221203
5232032211003
621002340335
73151414022
oct764165143
9303665255
10131132003
1168025462
1237aba6ab
1321223b02
14135b68b9
15b7a3dd8
hex7d0ea63

131132003 has 2 divisors, whose sum is σ = 131132004. Its totient is φ = 131132002.

The previous prime is 131131991. The next prime is 131132009. The reversal of 131132003 is 300231131.

It is a strong prime.

It is an emirp because it is prime and its reverse (300231131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131132003 - 28 = 131131747 is a prime.

It is not a weakly prime, because it can be changed into another prime (131132009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566001 + 65566002.

It is an arithmetic number, because the mean of its divisors is an integer number (65566002).

Almost surely, 2131132003 is an apocalyptic number.

131132003 is a deficient number, since it is larger than the sum of its proper divisors (1).

131132003 is an equidigital number, since it uses as much as digits as its factorization.

131132003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 131132003 is about 11451.2882681382. The cubic root of 131132003 is about 508.0458384971.

Adding to 131132003 its reverse (300231131), we get a palindrome (431363134).

The spelling of 131132003 in words is "one hundred thirty-one million, one hundred thirty-two thousand, three".