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13113223013441 is a prime number
BaseRepresentation
bin1011111011010010100011…
…1111111110010001000001
31201102121112001120112220202
42332310220333332101001
53204321340042412231
643520044222414545
72522253614341445
oct276645077762101
951377461515822
1013113223013441
1141a6317591581
12157951ba31455
13741757b20a65
1433497d2a4825
1517b1896c65cb
hexbed28ffe441

13113223013441 has 2 divisors, whose sum is σ = 13113223013442. Its totient is φ = 13113223013440.

The previous prime is 13113223013417. The next prime is 13113223013447. The reversal of 13113223013441 is 14431032231131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12955392409600 + 157830603841 = 3599360^2 + 397279^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113223013441 - 214 = 13113222997057 is a prime.

It is not a weakly prime, because it can be changed into another prime (13113223013447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556611506720 + 6556611506721.

It is an arithmetic number, because the mean of its divisors is an integer number (6556611506721).

Almost surely, 213113223013441 is an apocalyptic number.

It is an amenable number.

13113223013441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113223013441 is an equidigital number, since it uses as much as digits as its factorization.

13113223013441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13113223013441 its reverse (14431032231131), we get a palindrome (27544255244572).

The spelling of 13113223013441 in words is "thirteen trillion, one hundred thirteen billion, two hundred twenty-three million, thirteen thousand, four hundred forty-one".