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131132322001 is a prime number
BaseRepresentation
bin111101000100000011…
…0000111000011010001
3110112110211121011101201
41322020012013003101
54122024333301001
6140124044431201
712321403226452
oct1721006070321
9415424534351
10131132322001
115068186043a
12214b7b48501
13c49a661355
1464bda1d129
153627481501
hex1e881870d1

131132322001 has 2 divisors, whose sum is σ = 131132322002. Its totient is φ = 131132322000.

The previous prime is 131132321987. The next prime is 131132322089. The reversal of 131132322001 is 100223231131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104603730625 + 26528591376 = 323425^2 + 162876^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131132322001 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131132322001.

It is not a weakly prime, because it can be changed into another prime (131132322301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566161000 + 65566161001.

It is an arithmetic number, because the mean of its divisors is an integer number (65566161001).

Almost surely, 2131132322001 is an apocalyptic number.

It is an amenable number.

131132322001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131132322001 is an equidigital number, since it uses as much as digits as its factorization.

131132322001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 131132322001 its reverse (100223231131), we get a palindrome (231355553132).

The spelling of 131132322001 in words is "one hundred thirty-one billion, one hundred thirty-two million, three hundred twenty-two thousand, one".