Base | Representation |
---|---|
bin | 111101000100000011… |
… | …0001001101111010011 |
3 | 110112110211121201111111 |
4 | 1322020012021233103 |
5 | 4122024334124021 |
6 | 140124044554151 |
7 | 12321403303531 |
oct | 1721006115723 |
9 | 415424551444 |
10 | 131132333011 |
11 | 50681868739 |
12 | 214b7b52957 |
13 | c49a666374 |
14 | 64bda23151 |
15 | 36274848e1 |
hex | 1e88189bd3 |
131132333011 has 2 divisors, whose sum is σ = 131132333012. Its totient is φ = 131132333010.
The previous prime is 131132332993. The next prime is 131132333053. The reversal of 131132333011 is 110333231131.
It is a weak prime.
It is an emirp because it is prime and its reverse (110333231131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131132333011 - 225 = 131098778579 is a prime.
It is a super-2 number, since 2×1311323330112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131132933011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566166505 + 65566166506.
It is an arithmetic number, because the mean of its divisors is an integer number (65566166506).
Almost surely, 2131132333011 is an apocalyptic number.
131132333011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131132333011 is an equidigital number, since it uses as much as digits as its factorization.
131132333011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 131132333011 its reverse (110333231131), we get a palindrome (241465564142).
The spelling of 131132333011 in words is "one hundred thirty-one billion, one hundred thirty-two million, three hundred thirty-three thousand, eleven".
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