Base | Representation |
---|---|
bin | 111101000100000100… |
… | …0101100111001110011 |
3 | 110112110212212200021002 |
4 | 1322020020230321303 |
5 | 4122030022020311 |
6 | 140124111152215 |
7 | 12321412056143 |
oct | 1721010547163 |
9 | 415425780232 |
10 | 131133001331 |
11 | 50682184872 |
12 | 214b821566b |
13 | c49a83b617 |
14 | 64bdb58923 |
15 | 362756793b |
hex | 1e8822ce73 |
131133001331 has 4 divisors (see below), whose sum is σ = 131133726672. Its totient is φ = 131132275992.
The previous prime is 131133001291. The next prime is 131133001333. The reversal of 131133001331 is 133100331131.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 131133001331 - 226 = 131065892467 is a prime.
It is a super-2 number, since 2×1311330013312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131133001333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151466 + ... + 534048.
It is an arithmetic number, because the mean of its divisors is an integer number (32783431668).
Almost surely, 2131133001331 is an apocalyptic number.
131133001331 is a deficient number, since it is larger than the sum of its proper divisors (725341).
131133001331 is an equidigital number, since it uses as much as digits as its factorization.
131133001331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 725340.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 131133001331 its reverse (133100331131), we get a palindrome (264233332462).
The spelling of 131133001331 in words is "one hundred thirty-one billion, one hundred thirty-three million, one thousand, three hundred thirty-one".
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