131133113113 has 4 divisors (see below), whose sum is σ = 135363213568. Its totient is φ = 126903012660.

The previous prime is 131133113107. The next prime is 131133113149. The reversal of 131133113113 is 311311331131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131133113113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131133113173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2115050181 + ... + 2115050242.

It is an arithmetic number, because the mean of its divisors is an integer number (33840803392).

Almost surely, 2^131133113113 is an apocalyptic number.

It is an amenable number.

131133113113 is a deficient number, since it is larger than the sum of its proper divisors (4230100455).

131133113113 is an equidigital number, since it uses as much as digits as its factorization.

131133113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4230100454.

The product of its digits is 243, while the sum is 22.

Adding to 131133113113 its reverse (311311331131), we get a palindrome (442444444244).

The spelling of 131133113113 in words is "one hundred thirty-one billion, one hundred thirty-three million, one hundred thirteen thousand, one hundred thirteen".