13113321311081 has 2 divisors, whose sum is σ = 13113321311082. Its totient is φ = 13113321311080.

The previous prime is 13113321311053. The next prime is 13113321311117. The reversal of 13113321311081 is 18011312331131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8793953011600 + 4319368299481 = 2965460^2 + 2078309^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113321311081 - 2¹⁸ = 13113321048937 is a prime.

It is a super-3 number, since 3×13113321311081³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13113321317081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556660655540 + 6556660655541.

It is an arithmetic number, because the mean of its divisors is an integer number (6556660655541).

Almost surely, 2^{13113321311081} is an apocalyptic number.

It is an amenable number.

13113321311081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113321311081 is an equidigital number, since it uses as much as digits as its factorization.

13113321311081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 29.

The spelling of 13113321311081 in words is "thirteen trillion, one hundred thirteen billion, three hundred twenty-one million, three hundred eleven thousand, eighty-one".