1311332434441 has 2 divisors, whose sum is σ = 1311332434442. Its totient is φ = 1311332434440.

The previous prime is 1311332434427. The next prime is 1311332434457. The reversal of 1311332434441 is 1444342331131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1029260975625 + 282071458816 = 1014525^2 + 531104^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311332434441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311332434397 and 1311332434406.

It is not a weakly prime, because it can be changed into another prime (1311332434411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655666217220 + 655666217221.

It is an arithmetic number, because the mean of its divisors is an integer number (655666217221).

Almost surely, 2^{1311332434441} is an apocalyptic number.

It is an amenable number.

1311332434441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311332434441 is an equidigital number, since it uses as much as digits as its factorization.

1311332434441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 41472, while the sum is 34.

Adding to 1311332434441 its reverse (1444342331131), we get a palindrome (2755674765572).

The spelling of 1311332434441 in words is "one trillion, three hundred eleven billion, three hundred thirty-two million, four hundred thirty-four thousand, four hundred forty-one".