Base | Representation |
---|---|
bin | 11000011011001111… |
… | …01001101100110010 |
3 | 1020211220011202011201 |
4 | 30031213221230302 |
5 | 203324012300424 |
6 | 10005121401414 |
7 | 642651030133 |
oct | 141547515462 |
9 | 36756152151 |
10 | 13113400114 |
11 | 561a199661 |
12 | 265b79926a |
13 | 130ca27869 |
14 | 8c5847c8a |
15 | 51b3a1d44 |
hex | 30d9e9b32 |
13113400114 has 8 divisors (see below), whose sum is σ = 19939553820. Its totient is φ = 6466882176.
The previous prime is 13113400093. The next prime is 13113400129. The reversal of 13113400114 is 41100431131.
It can be written as a sum of positive squares in 2 ways, for example, as 11811994489 + 1301405625 = 108683^2 + 36075^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×131134001142 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13113400091 and 13113400100.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44908759 + ... + 44909050.
Almost surely, 213113400114 is an apocalyptic number.
13113400114 is a deficient number, since it is larger than the sum of its proper divisors (6826153706).
13113400114 is an equidigital number, since it uses as much as digits as its factorization.
13113400114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89817884.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 13113400114 its reverse (41100431131), we get a palindrome (54213831245).
The spelling of 13113400114 in words is "thirteen billion, one hundred thirteen million, four hundred thousand, one hundred fourteen".
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