131134020431131 has 4 divisors (see below), whose sum is σ = 132077430650200. Its totient is φ = 130190610212064.

The previous prime is 131134020431119. The next prime is 131134020431213.

131134020431131 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131134020431131 - 2⁷ = 131134020431003 is a prime.

It is a super-2 number, since 2×131134020431131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131134020431131.

It is not an unprimeable number, because it can be changed into a prime (131134020431831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 471705109326 + ... + 471705109603.

It is an arithmetic number, because the mean of its divisors is an integer number (33019357662550).

Almost surely, 2^{131134020431131} is an apocalyptic number.

131134020431131 is a deficient number, since it is larger than the sum of its proper divisors (943410219069).

131134020431131 is an equidigital number, since it uses as much as digits as its factorization.

131134020431131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 943410219068.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 131134020431131 in words is "one hundred thirty-one trillion, one hundred thirty-four billion, twenty million, four hundred thirty-one thousand, one hundred thirty-one".