13113411403 has 2 divisors, whose sum is σ = 13113411404. Its totient is φ = 13113411402.

The previous prime is 13113411287. The next prime is 13113411407. The reversal of 13113411403 is 30411431131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13113411403 is a prime.

It is not a weakly prime, because it can be changed into another prime (13113411407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556705701 + 6556705702.

It is an arithmetic number, because the mean of its divisors is an integer number (6556705702).

Almost surely, 2^13113411403 is an apocalyptic number.

13113411403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113411403 is an equidigital number, since it uses as much as digits as its factorization.

13113411403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13113411403 its reverse (30411431131), we get a palindrome (43524842534).

The spelling of 13113411403 in words is "thirteen billion, one hundred thirteen million, four hundred eleven thousand, four hundred three".