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131134212552553 = 724140997760021
BaseRepresentation
bin11101110100010000010000…
…001010000011011101101001
3122012022022022202000210121121
4131310100100022003131221
5114142000331403140203
61142522120421135241
736423064014266260
oct3564202012033551
9565268282023547
10131134212552553
1138868786362341
121285a83255a521
135822b983a78a2
142454d033535d7
15102617d8d20bd
hex774410283769

131134212552553 has 8 divisors (see below), whose sum is σ = 149867752881600. Its totient is φ = 112400692571760.

The previous prime is 131134212552529. The next prime is 131134212552569. The reversal of 131134212552553 is 355255212431131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131134212552553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131134212552593) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13018683 + ... + 20778703.

It is an arithmetic number, because the mean of its divisors is an integer number (18733469110200).

Almost surely, 2131134212552553 is an apocalyptic number.

It is an amenable number.

131134212552553 is a deficient number, since it is larger than the sum of its proper divisors (18733540329047).

131134212552553 is an equidigital number, since it uses as much as digits as its factorization.

131134212552553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10174127.

The product of its digits is 540000, while the sum is 43.

Adding to 131134212552553 its reverse (355255212431131), we get a palindrome (486389424983684).

The spelling of 131134212552553 in words is "one hundred thirty-one trillion, one hundred thirty-four billion, two hundred twelve million, five hundred fifty-two thousand, five hundred fifty-three".

Divisors: 1 7 2414099 7760021 16898693 54320147 18733458936079 131134212552553