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13113844140842 = 229226100761049
BaseRepresentation
bin1011111011010100111000…
…0001011000101100101010
31201102200010100100002112022
42332311032001120230222
53204324123100001332
643520230011344442
72522305166003504
oct276651601305452
951380110302468
1013113844140842
1141a660615a805
121579673a52122
13741826705c73
143349db98ad74
1517b1c3eb9212
hexbed4e058b2a

13113844140842 has 8 divisors (see below), whose sum is σ = 20349068494500. Its totient is φ = 6330821309344.

The previous prime is 13113844140763. The next prime is 13113844140853. The reversal of 13113844140842 is 24804144831131.

13113844140842 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 11772646214641 + 1341197926201 = 3431129^2 + 1158101^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13113844140793 and 13113844140802.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113050380467 + ... + 113050380582.

Almost surely, 213113844140842 is an apocalyptic number.

13113844140842 is a deficient number, since it is larger than the sum of its proper divisors (7235224353658).

13113844140842 is a wasteful number, since it uses less digits than its factorization.

13113844140842 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 226100761080.

The product of its (nonzero) digits is 294912, while the sum is 44.

Adding to 13113844140842 its reverse (24804144831131), we get a palindrome (37917988971973).

The spelling of 13113844140842 in words is "thirteen trillion, one hundred thirteen billion, eight hundred forty-four million, one hundred forty thousand, eight hundred forty-two".

Divisors: 1 2 29 58 226100761049 452201522098 6556922070421 13113844140842