131140205330401 has 4 divisors (see below), whose sum is σ = 132800207929600. Its totient is φ = 129480202731204.

The previous prime is 131140205330371. The next prime is 131140205330411. The reversal of 131140205330401 is 104033502041131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131140205330401 - 2⁵ = 131140205330369 is a prime.

It is a super-4 number, since 4×131140205330401⁴ (a number of 58 digits) contains 4444 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131140205330401.

It is not an unprimeable number, because it can be changed into a prime (131140205330411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 830001299481 + ... + 830001299638.

It is an arithmetic number, because the mean of its divisors is an integer number (33200051982400).

Almost surely, 2^{131140205330401} is an apocalyptic number.

It is an amenable number.

131140205330401 is a deficient number, since it is larger than the sum of its proper divisors (1660002599199).

131140205330401 is an equidigital number, since it uses as much as digits as its factorization.

131140205330401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1660002599198.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 131140205330401 its reverse (104033502041131), we get a palindrome (235173707371532).

The spelling of 131140205330401 in words is "one hundred thirty-one trillion, one hundred forty billion, two hundred five million, three hundred thirty thousand, four hundred one".