Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …010110000001111110001011 |
3 | 122012022222010111220201222222 |
4 | 131310112223112001332023 |
5 | 114142103443422043242 |
6 | 1142525221133404255 |
7 | 36423426662231054 |
oct | 3564265326017613 |
9 | 565288114821888 |
10 | 131141111127947 |
11 | 388706a6432118 |
12 | 1286003893968b |
13 | 582372768b76b |
14 | 245539962b72b |
15 | 10264343645d2 |
hex | 7745ab581f8b |
131141111127947 has 2 divisors, whose sum is σ = 131141111127948. Its totient is φ = 131141111127946.
The previous prime is 131141111127937. The next prime is 131141111127977. The reversal of 131141111127947 is 749721111141131.
It is a weak prime.
It is an emirp because it is prime and its reverse (749721111141131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131141111127947 - 218 = 131141110865803 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131141111127898 and 131141111127907.
It is not a weakly prime, because it can be changed into another prime (131141111127937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570555563973 + 65570555563974.
It is an arithmetic number, because the mean of its divisors is an integer number (65570555563974).
Almost surely, 2131141111127947 is an apocalyptic number.
131141111127947 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141111127947 is an equidigital number, since it uses as much as digits as its factorization.
131141111127947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 42336, while the sum is 44.
The spelling of 131141111127947 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, one hundred twenty-seven thousand, nine hundred forty-seven".
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