Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …010110010110101111001001 |
3 | 122012022222010112002001200010 |
4 | 131310112223112112233021 |
5 | 114142103443432304001 |
6 | 1142525221135302133 |
7 | 36423426663034041 |
oct | 3564265326265711 |
9 | 565288115061603 |
10 | 131141111213001 |
11 | 388706a649000a |
12 | 1286003897a949 |
13 | 58237276bb3a6 |
14 | 2455399650721 |
15 | 102643437e8d6 |
hex | 7745ab596bc9 |
131141111213001 has 32 divisors (see below), whose sum is σ = 175653860773248. Its totient is φ = 87029075427840.
The previous prime is 131141111212997. The next prime is 131141111213009. The reversal of 131141111213001 is 100312111141131.
It is not a de Polignac number, because 131141111213001 - 22 = 131141111212997 is a prime.
It is a super-2 number, since 2×1311411112130012 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131141111213009) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 910244511 + ... + 910388571.
It is an arithmetic number, because the mean of its divisors is an integer number (5489183149164).
Almost surely, 2131141111213001 is an apocalyptic number.
It is an amenable number.
131141111213001 is a deficient number, since it is larger than the sum of its proper divisors (44512749560247).
131141111213001 is a wasteful number, since it uses less digits than its factorization.
131141111213001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 146121.
The product of its (nonzero) digits is 72, while the sum is 21.
Adding to 131141111213001 its reverse (100312111141131), we get a palindrome (231453222354132).
The spelling of 131141111213001 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, two hundred thirteen thousand, one".
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