1311411131153 has 4 divisors (see below), whose sum is σ = 1311423437040. Its totient is φ = 1311398825268.

The previous prime is 1311411131119. The next prime is 1311411131183. The reversal of 1311411131153 is 3511311141131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311411131153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311411131183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5991683 + ... + 6206696.

It is an arithmetic number, because the mean of its divisors is an integer number (327855859260).

Almost surely, 2^{1311411131153} is an apocalyptic number.

It is an amenable number.

1311411131153 is a deficient number, since it is larger than the sum of its proper divisors (12305887).

1311411131153 is a wasteful number, since it uses less digits than its factorization.

1311411131153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12305886.

The product of its digits is 540, while the sum is 26.

Adding to 1311411131153 its reverse (3511311141131), we get a palindrome (4822722272284).

The spelling of 1311411131153 in words is "one trillion, three hundred eleven billion, four hundred eleven million, one hundred thirty-one thousand, one hundred fifty-three".