131141122431041 has 4 divisors (see below), whose sum is σ = 131141182306500. Its totient is φ = 131141062555584.

The previous prime is 131141122431037. The next prime is 131141122431071. The reversal of 131141122431041 is 140134221141131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12834277590016 + 118306844841025 = 3582496^2 + 10876895^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141122431041 - 2² = 131141122431037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131141122430995 and 131141122431013.

It is not an unprimeable number, because it can be changed into a prime (131141122431071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26522516 + ... + 31076133.

It is an arithmetic number, because the mean of its divisors is an integer number (32785295576625).

Almost surely, 2^{131141122431041} is an apocalyptic number.

It is an amenable number.

131141122431041 is a deficient number, since it is larger than the sum of its proper divisors (59875459).

131141122431041 is an equidigital number, since it uses as much as digits as its factorization.

131141122431041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59875458.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 131141122431041 its reverse (140134221141131), we get a palindrome (271275343572172).

The spelling of 131141122431041 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twenty-two million, four hundred thirty-one thousand, forty-one".