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131141123223041 is a prime number
BaseRepresentation
bin11101110100010110101100…
…000100001010111000000001
3122012022222011100200020100102
4131310112230010022320001
5114142104010021114131
61142525222244532145
736423430200104531
oct3564265404127001
9565288140606312
10131141123223041
1138870702243368
12128600409b1055
13582372a034b19
14245539b0994c1
1510264354531cb
hex7745ac10ae01

131141123223041 has 2 divisors, whose sum is σ = 131141123223042. Its totient is φ = 131141123223040.

The previous prime is 131141123223023. The next prime is 131141123223067. The reversal of 131141123223041 is 140322321141131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109865930073025 + 21275193150016 = 10481695^2 + 4612504^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141123223041 - 222 = 131141119028737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131141123222995 and 131141123223013.

It is not a weakly prime, because it can be changed into another prime (131141123213041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570561611520 + 65570561611521.

It is an arithmetic number, because the mean of its divisors is an integer number (65570561611521).

Almost surely, 2131141123223041 is an apocalyptic number.

It is an amenable number.

131141123223041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141123223041 is an equidigital number, since it uses as much as digits as its factorization.

131141123223041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 131141123223041 its reverse (140322321141131), we get a palindrome (271463444364172).

The spelling of 131141123223041 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twenty-three million, two hundred twenty-three thousand, forty-one".