1311411330403 has 4 divisors (see below), whose sum is σ = 1311417537768. Its totient is φ = 1311405123040.

The previous prime is 1311411330311. The next prime is 1311411330409. The reversal of 1311411330403 is 3040331141131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311411330403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311411330409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2775193 + ... + 3213178.

It is an arithmetic number, because the mean of its divisors is an integer number (327854384442).

Almost surely, 2^{1311411330403} is an apocalyptic number.

1311411330403 is a deficient number, since it is larger than the sum of its proper divisors (6207365).

1311411330403 is an equidigital number, since it uses as much as digits as its factorization.

1311411330403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6207364.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1311411330403 its reverse (3040331141131), we get a palindrome (4351742471534).

The spelling of 1311411330403 in words is "one trillion, three hundred eleven billion, four hundred eleven million, three hundred thirty thousand, four hundred three".