Base | Representation |
---|---|
bin | 1011111011010101111010… |
… | …1001101001010011111011 |
3 | 1201102200211210022012212001 |
4 | 2332311132221221103323 |
5 | 3204330211010130412 |
6 | 43520313415201431 |
7 | 2522315124244336 |
oct | 276653651512373 |
9 | 51380753265761 |
10 | 13114123130107 |
11 | 41a673969354a |
12 | 1579731376277 |
13 | 74186c45857c |
14 | 334a26a5161d |
15 | 17b1dd727957 |
hex | bed5ea694fb |
13114123130107 has 2 divisors, whose sum is σ = 13114123130108. Its totient is φ = 13114123130106.
The previous prime is 13114123129997. The next prime is 13114123130113. The reversal of 13114123130107 is 70103132141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13114123130107 - 211 = 13114123128059 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114123137107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557061565053 + 6557061565054.
It is an arithmetic number, because the mean of its divisors is an integer number (6557061565054).
Almost surely, 213114123130107 is an apocalyptic number.
13114123130107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114123130107 is an equidigital number, since it uses as much as digits as its factorization.
13114123130107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 13114123130107 its reverse (70103132141131), we get a palindrome (83217255271238).
The spelling of 13114123130107 in words is "thirteen trillion, one hundred fourteen billion, one hundred twenty-three million, one hundred thirty thousand, one hundred seven".
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