Base | Representation |
---|---|
bin | 10011000101010110010… |
… | …011100101101111000001 |
3 | 11122100222121220222112120 |
4 | 103011112103211233001 |
5 | 132441233212014103 |
6 | 2442242123514453 |
7 | 163514015405253 |
oct | 23052623455701 |
9 | 4570877828476 |
10 | 1311413001153 |
11 | 4661924a5952 |
12 | 1921b1688a29 |
13 | 96886765c68 |
14 | 47689245cd3 |
15 | 241a5d95253 |
hex | 131564e5bc1 |
1311413001153 has 8 divisors (see below), whose sum is σ = 1789214637408. Its totient is φ = 853943349504.
The previous prime is 1311413001139. The next prime is 1311413001187. The reversal of 1311413001153 is 3511003141131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1311413001153 - 210 = 1311413000129 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1311413001553) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5082996000 + ... + 5082996257.
It is an arithmetic number, because the mean of its divisors is an integer number (223651829676).
Almost surely, 21311413001153 is an apocalyptic number.
It is an amenable number.
1311413001153 is a deficient number, since it is larger than the sum of its proper divisors (477801636255).
1311413001153 is a wasteful number, since it uses less digits than its factorization.
1311413001153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10165992303.
The product of its (nonzero) digits is 540, while the sum is 24.
Adding to 1311413001153 its reverse (3511003141131), we get a palindrome (4822416142284).
The spelling of 1311413001153 in words is "one trillion, three hundred eleven billion, four hundred thirteen million, one thousand, one hundred fifty-three".
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