Base | Representation |
---|---|
bin | 11101110100010110110111… |
… | …011101100101000100101011 |
3 | 122012022222122200110201112201 |
4 | 131310112313131211010223 |
5 | 114142104402443331243 |
6 | 1142525253235121031 |
7 | 36423435011263105 |
oct | 3564266735450453 |
9 | 565288580421481 |
10 | 131141314433323 |
11 | 388707a0172497 |
12 | 12860094a43177 |
13 | 582375a8323bc |
14 | 24553b8630575 |
15 | 102644712304d |
hex | 7745b776512b |
131141314433323 has 2 divisors, whose sum is σ = 131141314433324. Its totient is φ = 131141314433322.
The previous prime is 131141314433303. The next prime is 131141314433329. The reversal of 131141314433323 is 323334413141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131141314433323 - 25 = 131141314433291 is a prime.
It is a super-2 number, since 2×1311413144333232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131141314433329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570657216661 + 65570657216662.
It is an arithmetic number, because the mean of its divisors is an integer number (65570657216662).
Almost surely, 2131141314433323 is an apocalyptic number.
131141314433323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141314433323 is an equidigital number, since it uses as much as digits as its factorization.
131141314433323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 93312, while the sum is 37.
Adding to 131141314433323 its reverse (323334413141131), we get a palindrome (454475727574454).
The spelling of 131141314433323 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred fourteen million, four hundred thirty-three thousand, three hundred twenty-three".
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