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131141324013419 is a prime number
BaseRepresentation
bin11101110100010110111000…
…000010000111111101101011
3122012022222200100111102222002
4131310112320002013331223
5114142104412421412134
61142525254220321215
736423435155563316
oct3564267002077553
9565288610442862
10131141324013419
11388707a5616125
12128600980a320b
13582375c807ab5
1424553b9a0597d
151026447db687e
hex7745b8087f6b

131141324013419 has 2 divisors, whose sum is σ = 131141324013420. Its totient is φ = 131141324013418.

The previous prime is 131141324013407. The next prime is 131141324013439. The reversal of 131141324013419 is 914310423141131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131141324013419 - 216 = 131141323947883 is a prime.

It is a super-3 number, since 3×1311413240134193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (131141324013439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570662006709 + 65570662006710.

It is an arithmetic number, because the mean of its divisors is an integer number (65570662006710).

Almost surely, 2131141324013419 is an apocalyptic number.

131141324013419 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141324013419 is an equidigital number, since it uses as much as digits as its factorization.

131141324013419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 38.

The spelling of 131141324013419 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, thirteen thousand, four hundred nineteen".