Base | Representation |
---|---|
bin | 11101110100010110111000… |
… | …000010000111111101101011 |
3 | 122012022222200100111102222002 |
4 | 131310112320002013331223 |
5 | 114142104412421412134 |
6 | 1142525254220321215 |
7 | 36423435155563316 |
oct | 3564267002077553 |
9 | 565288610442862 |
10 | 131141324013419 |
11 | 388707a5616125 |
12 | 128600980a320b |
13 | 582375c807ab5 |
14 | 24553b9a0597d |
15 | 1026447db687e |
hex | 7745b8087f6b |
131141324013419 has 2 divisors, whose sum is σ = 131141324013420. Its totient is φ = 131141324013418.
The previous prime is 131141324013407. The next prime is 131141324013439. The reversal of 131141324013419 is 914310423141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141324013419 - 216 = 131141323947883 is a prime.
It is a super-3 number, since 3×1311413240134193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (131141324013439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570662006709 + 65570662006710.
It is an arithmetic number, because the mean of its divisors is an integer number (65570662006710).
Almost surely, 2131141324013419 is an apocalyptic number.
131141324013419 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141324013419 is an equidigital number, since it uses as much as digits as its factorization.
131141324013419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 38.
The spelling of 131141324013419 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, thirteen thousand, four hundred nineteen".
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