Base | Representation |
---|---|
bin | 11101110100010110111000… |
… | …000011010000011110000010 |
3 | 122012022222200101001112100110 |
4 | 131310112320003100132002 |
5 | 114142104413010413102 |
6 | 1142525254230532150 |
7 | 36423435161241210 |
oct | 3564267003203602 |
9 | 565288611045313 |
10 | 131141324310402 |
11 | 388707a57a926a |
12 | 12860098207056 |
13 | 582375c8b0023 |
14 | 24553b9a81cb0 |
15 | 1026447e2486c |
hex | 7745b80d0782 |
131141324310402 has 64 divisors (see below), whose sum is σ = 301015230935040. Its totient is φ = 37311005579904.
The previous prime is 131141324310343. The next prime is 131141324310457. The reversal of 131141324310402 is 204013423141131.
131141324310402 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a self number, because there is not a number n which added to its sum of digits gives 131141324310402.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 349566558 + ... + 349941510.
It is an arithmetic number, because the mean of its divisors is an integer number (4703362983360).
Almost surely, 2131141324310402 is an apocalyptic number.
131141324310402 is an abundant number, since it is smaller than the sum of its proper divisors (169873906624638).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131141324310402 is a wasteful number, since it uses less digits than its factorization.
131141324310402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 410047.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 131141324310402 its reverse (204013423141131), we get a palindrome (335154747451533).
The spelling of 131141324310402 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, three hundred ten thousand, four hundred two".
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