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13114132431120 = 243457289112267
BaseRepresentation
bin1011111011010101111100…
…1101001000000100010000
31201102200212102210202110000
42332311133031020010100
53204330220400243440
643520314350410000
72522315266303110
oct276653715100420
951380772722400
1013114132431120
1141a6743966536
121579734500900
13741871363c26
14334a27d93040
1517b1de463730
hexbed5f348110

13114132431120 has 200 divisors, whose sum is σ = 52054085628864. Its totient is φ = 2997515973888.

The previous prime is 13114132431061. The next prime is 13114132431149. The reversal of 13114132431120 is 2113423141131.

13114132431120 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 4 + 1 + 324 + 311 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 144510774 + ... + 144601493.

Almost surely, 213114132431120 is an apocalyptic number.

13114132431120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13114132431120 is an abundant number, since it is smaller than the sum of its proper divisors (38939953197744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114132431120 is a wasteful number, since it uses less digits than its factorization.

13114132431120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 289112299 (or 289112284 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 13114132431120 its reverse (2113423141131), we get a palindrome (15227555572251).

The spelling of 13114132431120 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred thirty-one thousand, one hundred twenty".