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131141330121121 is a prime number
BaseRepresentation
bin11101110100010110111000…
…011001011011000110100001
3122012022222200202222202011021
4131310112320121123012201
5114142104421002333441
61142525254555245441
736423435261522115
oct3564267031330641
9565288622882137
10131141330121121
11388707a9007a11
121286009a149881
135823760b65b18
1424553ba755745
1510264486c13d1
hex7745b865b1a1

131141330121121 has 2 divisors, whose sum is σ = 131141330121122. Its totient is φ = 131141330121120.

The previous prime is 131141330121097. The next prime is 131141330121133. The reversal of 131141330121121 is 121121033141131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97043777166400 + 34097552954721 = 9851080^2 + 5839311^2 .

It is an emirp because it is prime and its reverse (121121033141131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131141330121121 - 29 = 131141330120609 is a prime.

It is not a weakly prime, because it can be changed into another prime (131141330421121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570665060560 + 65570665060561.

It is an arithmetic number, because the mean of its divisors is an integer number (65570665060561).

Almost surely, 2131141330121121 is an apocalyptic number.

It is an amenable number.

131141330121121 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141330121121 is an equidigital number, since it uses as much as digits as its factorization.

131141330121121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 131141330121121 its reverse (121121033141131), we get a palindrome (252262363262252).

The spelling of 131141330121121 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred thirty million, one hundred twenty-one thousand, one hundred twenty-one".